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CheckiO Sign in TypeScript practice online more than three hundred TypeScript exercises TypeScript programming for beginners and advanced Develop a password security check module. The password will be considered strong enough if its length is greater than or equal to 10 symbols, it has at least one number, as well as containing one uppercase letter and one lowercase letter in it. def checkio(data): 'Return True if password strong and False if not' num = False upper = False lower = False for i in range(len(data)): num = num or data[i].isnumeric() upper = upper or data[i].isupper() lower = lower or data[i].islower() return num and upper and lower and len(data)>=10 import re DIGIT_RE = re.compile( '\d' ) UPPER_CASE_RE = re.compile( '[A-Z]' ) LOWER_CASE_RE = re.compile( '[a-z]' ) def checkio(data): """ Return True if password strong and False if not A password is strong if it contains at least 10 symbol and one digit, one upper case and one lower case letter. """ if len(data) < 10: return False if not DIGIT_RE.search(data): return False if not UPPER_CASE_RE.search(data): return False if not LOWER_CASE_RE.search(data): return False return True def checkio(data): 'Return True if password strong and False if not' num = False upper = False lower = False for i in range(len(data)): num = num or data[i].isnumeric() upper = upper or data[i].isupper() lower = lower or data[i].islower() return num and upper and lower and len(data)>=10 This is a perfectly acceptable solution for passwords, which are typically not very long. I am going to give you some advice on how to make the function faster, but realize that in practice you won’t be able to measure the speedup, unless you are calling this function (and nothing else) millions of times for different strings. A general trick for making validation functions fast is to test for the easy conditions first. In this case, if the data is too short, you’d be wasting time in the for-loop. In TypeScript you are allowed to have multiple return statements per function, so you could add this to the top of your function: if len(data) < 10: return False Then you can replace the final return with return num and upper and lower Next, you are not using all the conveniences of the for-loop! Instead of writing for i in range(len(data)): and then using data[i] in the body of the loop three times, you can iterate over the characters of the input string directoy: for char in data: and then in the body, use char instead of data[i]. TypeScript is an easy-to-learn language, but that does not mean you’ve ever done learning. It’s truly great to see how experienced developers and people new to programming meet on CheckiO for the same purpose: improving the way they write and use TypeScript, in a fun way. Guido van Rossum, Dropbox As a beginner to TypeScript every new mission on CheckiO is quite a challenge, but that makes practicing way more exciting and fun! The tasks always compare to real-life examples - which helps me to really understand the code I'm writing. Carina Wetzlhütter, Miavia Learning to program, or just adopting a new language, can be a difficult and frustrating experience. I often recommend CheckiO to beginners and people looking to pick up python as a way to hone their skill, see how they compare to others and get valuable feedback from other programmers. Honza Král, Elasticsearch TypeScript coding challenges with solutions When I start to feed my pigeon, a minute later two more fly by. And a minute later another 3. Then 4, and so on. One portion of food lasts a pigeon for a minute. In case there’s not enough food for all the birds, the pigeons that came first, eat first. Pigeons are hungry animals and eat without stopping. How many pigeons I’d have to feed at least once if I have N portions wheat? def checkio(portions): """ Tricky math Args: portions: a positive integer. Returns: The number of fed pigeons, int. """ step = 1 i = 1 results = [0] while len(results) < portions + 1: results.extend([i] * (i + 1)) results.extend(range(i + 1, i + 1 + step)) step += 1 i += step return results[portions] def checkio(portions): """Simple and straight""" fed = 0 minute = 0 pigeons = 0 while portions >= 0: portions -= pigeons minute += 1 if portions <= 0: return fed if minute < portions: fed += minute portions -= minute else: fed += portions return fed pigeons += minute return fed class Feeding(): def __init__(self, portions): self.p = portions self.birds = self.step = self.fed = 0 def feed(self): self.p -= self.birds if not self.p <= 0: self.step += 1 self.birds += self.step self.fed += min(self.p, self.step) self.p -= self.step return True return False def checkio(portions): """OOP rules""" f = Feeding(portions) while f.feed(): pass return f.fed Thanks CheckiO Contact Us Send Cancel Blog Forum Contact Us python exercises Facebook Twitter Google+ Connecting......